∫e^x*tan(x-1)^2dx

∫e^x*tan(x-1)^2dx 求解不定积分∫(e^(2x))(tan X+1)^2dx的详细过程 ∫(e^x) tan (e^x )dx求不定积分! ∫[dx/(e^x(1+e^2x)]dx 求∫x*tan^2x dx 求∫1／tan^2x+sin^2x dx ∫sec^2 x / √ tan x +1 dx ∫ ( tan^2 x + tan^4 x )dx 求不定积分∫(tan^2x+tan^4x)dx ￡tan x(tan x+1)dx ∫ e^x-e^(-x)dx=e^x+e^(-x)|=e+1/e-2 ∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 求不定积分 ∫ tan^2 x dx 求不定积分∫(tan^2)x dx ∫ tan(2x-5)dx= ∫1/(e^x+e^(-x))dx, ∫(1+tan^2x)dx/(1+tanx)^3