∫(1+tan^2x)dx/(1+tanx)^3

￡tan x(tan x+1)dx 求∫1／tan^2x+sin^2x dx ∫sec^2 x / √ tan x +1 dx ∫e^x*tan(x-1)^2dx ∫(1+tan^2x)dx/(1+tanx)^3 ∫ ( tan^2 x + tan^4 x )dx 求不定积分∫(tan^2x+tan^4x)dx 求∫x*tan^2x dx 求不定积分 ∫ tan^2 x dx 求不定积分∫(tan^2)x dx ∫ tan(2x-5)dx= 两道不定积分的题(1)∫(1-tan x)/(1+tan x)dx(2)∫1/[5(cos x)^2+3(sin x)^2]dx ∫tan^3x dx ∫tan√(1+x^2)*x/(√1+x^2)dx 求不定积分∫(tan^2+2)dx∫(tan^2x+2)dx ∫[tan(3x+1)/cos^2(3x+1)]dx如何计算, 求∫(1/x^2)tan(1/x)dx的不定积分 求不定积分∫[tan^2x/(1-sin^2x)]dx