2^[1+（1/2）^log2 5]=?我解的是2^[1+(2^log2 5)^-1]=2^(6/5)而答案是2^[1+（1/2）^log2 5]=2×（2^log2 5)^1/2=2×5^(1/2)=2√5我的答案哪里错了

计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 解2log2^(x-5)=log2^(x-1)+1 4^1/2（log2^9-log2^5）的值 , 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 解方程log2(2-x)=log2(x-1)+1 已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f（x）=log2（2x）×log2（x／4）＝[（log2 2）+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2 求解log2(3x)=log2(2x+1) |[log2(x)]^2-3log2(x)+1| (log2)2+log2*log50+1g25值 log2(2^x-1)log2(2^(x+2)-4=3log2(2^x-1)log2(2^(x+2)-4）=3 下面的2是底数log2(1+tan1度）+log2(1+tan2度）+...log2(1+tan44度)+log2(1+tan45度)=? log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底 lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )