(n+1)2÷(n+1)2+1=0.
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 19:52:08
(n+1)2÷(n+1)2+1=0.(n+1)2÷(n+1)2+1=0.(n+1)2÷(n+1)2+1=0."设(n+1)2=x(x≥0)则有:x/(x+1)=0.98x=0.98x+0.980.02
(n+1)2÷(n+1)2+1=0.
(n+1)2÷(n+1)2+1=0.
(n+1)2÷(n+1)2+1=0.
"设(n+1)2=x(x≥0)
则有:
x/(x+1)=0.98
x=0.98x+0.98
0.02x=0.98
x=49
(n+1)2=x=49
n+1=±7
所以
n=8或n=-6"
应该是:
n=6
或
n=-8"
2^n/n*(n+1)
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
n+(n-1)÷2×n 求化简
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n
2n*1/2^n=n/2^(n-1)?
阶乘(2n-1)!=(2n)!/(2^n*n!
为什么n!/(2!(n-2)!)=n(n-1)/2!
高数题:n趋近于0,lim{1/(n^2+n+1)+2/(n^2+n+2)+3/(n^2+n+3)+.+n/(n^2+n+n)}=?
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
(n+2)!/(n+1)!
为什么:n×(n+1)=1/3[n(n+1)×(n+2)-(n-1)×n×(n+1)]
为什么n(n+1)(n+2)(n+3)=(n²+3n+2)(n²+3n)?
n(n+1)/1+(n+1)(n+2)/1+.+(n+2007)(n+2008)/1=?
数列a(n)=n (n+1)(n+2)(n+3),求S(n)
n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10这道题怎么解
n(n-1)(n-2)(n-3)(n-4)=154440.求N值 要步骤
证明:c(n,0)c(n,1)+c(n,1)c(n,2)+...c(n,n-1)c(n,n)=c(2n,n-1)