若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
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若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.是平方吧原式:(x-
若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
是平方吧
原式:(x-y)²+(y-1)²=0
得x=y y=1
所以xy=1*1=1
回答完毕~
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