f(x)=1-2sin^2(x+兀/8)+2sin(x+兀/8)cos(x+兀/8) 求f(x)的最小正周期第2问:f(x)的单调增区间

f(sin 2/x )=1+cosx 求f(x) 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)cos(x+π/8) f(sin^2x)=x/sinx 求f(x) f(x)={(1-e^x)/sin(x/2) ,x>0 ;ae^2x,x f(x)=1-2sin^2(x+兀/8)+2sin(x+兀/8)cos(x+兀/8) 求f(x)的最小正周期第2问:f(x)的单调增区间 设函数f(x)=sin(2x+∮)(-兀 f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) f(x)=sin^2x+sinxcosx-1/2,化简 f(x)=(1+1/tanx)sin(x)^2化简 化简f(x)=(1+cos2x)sin^2x f(x)=sin(πx^2)(-1 已知函数f(x)=cos(x-3/ 兀)-sin(2/兀-x).(1)求函数f(x)的最小值. 已知函数f(x)=-1/2+sin(5/2x)/2sin(x/2)(0 若f(x)=sin πx/6,则f(1)+f(2)+...+f(102)=? 若f(x)=sin(π/4)x,求f(1)+f(2)+.+f(2010) 已知f(sin-1)=cos2x+2,求f(x)