log a^m(b^n)=(n/m)*log a(b)
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loga^m(b^n)=(n/m)*loga(b)loga^m(b^n)=(n/m)*loga(b)loga^m(b^n)=(n/m)*loga(b)loga^m(b^n)=[logx(b^n)]/[
log a^m(b^n)=(n/m)*log a(b)
log a^m(b^n)=(n/m)*log a(b)
log a^m(b^n)=(n/m)*log a(b)
log a^m(b^n)
=[logx(b^n)]/[logx(a^m)] ……………………这是换底公式
=[nlogx(b)]/[mlogx(a)] …………………………分子分母都用基本运算公式
=(n/m)loga(b) …………………………再用一次换底公式
log(a)M+log(a)N=?
证明a(log(m)n)=n(log(m)a)
log a (m^n)=(log a m)^n?
证明log(a^m)b^n=(n/m)log(a)b
log a^m(b^n)=(n/m)*log a(b)
求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(b)(a) 的推导
换底公式推导过程1.log(a)(b)=1/log(b)(a) 2.log(a^n)(b^m)=m/n*[log(a)(b)] 3.log(a)(M^n)=nlog(a)(M)
求证 log(a) (M·N)=log(a) M+log(a) N
log(下标a)(M*N)是什么意思?= log(下标a)M+log(下标a)N
证明：log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.
log(a^n)M= 1/n log(a)(M) log(a^n)M= n log(a)(M) 哪个对啊求神回复
推导log(a)(M/N)
log a b^n/log a a^m 什么运算法则得log a b^n/m
为什么-log（M/N)=log(N/M)
log（a^N)(b^M)=M/Nlog(a)(b)怎么推导?
为什么log(a^n)(M)=1/n×log(a)(M)
对数换底公式证明?log a^m b^n= n/m log a b 为什么我证明出来是=m/nlog a b
证明：log(a)(M^n)=nlog(a)(M)