证明log(a^m)b^n=(n/m)log(a)b
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证明log(a^m)b^n=(n/m)log(a)b证明log(a^m)b^n=(n/m)log(a)b证明log(a^m)b^n=(n/m)log(a)b证明:log(a^m)b^n=(lgb^n)
证明log(a^m)b^n=(n/m)log(a)b
证明log(a^m)b^n=(n/m)log(a)b
证明log(a^m)b^n=(n/m)log(a)b
证明:
log(a^m)b^n
=(lgb^n)/(lga^m)
=(n*lgb)/(m*lga)
=(n/m)*log(a)b
得证
证明a(log(m)n)=n(log(m)a)
证明log(a^m)b^n=(n/m)log(a)b
证明:log(a)(M^n)=nlog(a)(M)
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对数换底公式证明?log a^m b^n= n/m log a b 为什么我证明出来是=m/nlog a b
log(a)M+log(a)N=?
log a (m^n)=(log a m)^n?
log a^m(b^n)=(n/m)*log a(b)
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求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(b)(a) 的推导
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换底公式推导过程1.log(a)(b)=1/log(b)(a) 2.log(a^n)(b^m)=m/n*[log(a)(b)] 3.log(a)(M^n)=nlog(a)(M)
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(1)利用关系式log(a)N=ba^b=N证明换底公式 log(a)N=log(m)N/log(m)a (2)利用(1)中的换底公式求下式的值 log(2)25*log(3)4*log(5)9 (3)利用(1)中的换底公式证明 log(a)b*log(b)c*log(c)a=1
(1)利用关系式log(a)N=ba^b=N证明换底公式 log(a)N=log(m)N/log(m)a (2)利用(1)中的换底公式求下式的值 log(2)25*log(3)4*log(5)9 (3)利用(1)中的换底公式证明 log(a)b*log(b)c*log(c)a=1