为什么log(a^n)(M)=1/n×log(a)(M)
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为什么log(a^n)(M)=1/n×log(a)(M)为什么log(a^n)(M)=1/n×log(a)(M)为什么log(a^n)(M)=1/n×log(a)(M)两边分别以a^n为底做指数运算:
为什么log(a^n)(M)=1/n×log(a)(M)
为什么log(a^n)(M)=1/n×log(a)(M)
为什么log(a^n)(M)=1/n×log(a)(M)
两边分别以a^n为底做指数运算:
(a^n)^[log(a^n)(M)]=(a^n)^[1/n×log(a)(M)]
左边化简得:M 右边也为M
由指数函数的单调性可得log(a^n)(M)=1/n×log(a)(M).
为什么log(a^n)(M)=1/n×log(a)(M)
log(a)M+log(a)N=?
为什么-log(M/N)=log(N/M)
证明a(log(m)n)=n(log(m)a)
log a (m^n)=(log a m)^n?
log(a^n)M= 1/n log(a)(M) log(a^n)M= n log(a)(M) 哪个对啊求神回复
log(a)(mn)=log(a)(m)+log(a)(n)为什么呀?
证明对数运算法则(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N);(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N); (3)log(a)(M^n)=nlog(a)(M) (n∈R)
log(a^n)(M)=1/nlog(a)(M)..
求证 log(a) (M·N)=log(a) M+log(a) N
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换底公式推导过程1.log(a)(b)=1/log(b)(a) 2.log(a^n)(b^m)=m/n*[log(a)(b)] 3.log(a)(M^n)=nlog(a)(M)
推导log(a)(M/N)
log(a^n)M=1/n×log(a) M,用对数换底公式怎么证明
对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么?
对数运算有这样的公式么?log(a^n)(M)=1/n*log(a)(M)
证明log(a^m)b^n=(n/m)log(a)b
log a^m(b^n)=(n/m)*log a(b)