x^an-1÷x^2n-1·x^2n+1
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x^an-1÷x^2n-1·x^2n+1x^an-1÷x^2n-1·x^2n+1x^an-1÷x^2n-1·x^2n+1
x^an-1÷x^2n-1·x^2n+1
x^an-1÷x^2n-1·x^2n+1
x^an-1÷x^2n-1·x^2n+1
x^an-1÷x^2n-1·x^2n+1
(-x^2n-2)(-x)^5÷[x^n+1·x^n`(-x)]
x^(n)*x^(n+1)+x^(2n)*x
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an
(4x^n-2x^n-1-3x^n+2)÷(-5x^n-1)
因式分解:(x^n+1)+(2x^n)+(x^n-1)
x^n+1-2x^n+x^n-1因式分解
x^n-1-2x^n+x^n-1因式分解
若(x^2+1/x)^n(n∈N+,n
分解因式x^n-x^(n-1)+x^(n-2)
(-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=?
x^n-2x^n+1,因式分解
x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x
(-x)^3x^n-1+x^2n(-x)^3
已知 x ^3n-2 ÷x^ n+1 =x^3-n×x^n+2,求n的值
设an是函数f(x)=x^3+n^2*x-1的零点,证明;n/(n+1)
若[1+x]+[1+x]^2+[1+x]^3+.+[1+x]^n=a0+a1*x+a2*x^2+a3*x^3+.an*x^n,且a1+a2+a3+.+an-1=29-n,则n为多少