x^an-1÷x^2n-1·x^2n+1

x^an-1÷x^2n-1·x^2n+1 (-x^2n-2)(-x)^5÷[x^n+1·x^n`(-x)] x^(n)*x^(n+1)+x^(2n)*x f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n 【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解 若(x^2+1/x)^n(n∈N+,n 分解因式x^n-x^(n-1)+x^(n-2) (-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=? x^n-2x^n+1,因式分解 x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x (-x)^3x^n-1+x^2n(-x)^3 已知 x ^3n-2 ÷x^ n+1 =x^3-n×x^n+2,求n的值 设an是函数f(x)=x^3+n^2*x-1的零点,证明;n/(n+1) 若[1+x]+[1+x]^2+[1+x]^3+.+[1+x]^n=a0+a1*x+a2*x^2+a3*x^3+.an*x^n,且a1+a2+a3+.+an-1=29-n,则n为多少