x+3y+4z=3 x+5y+9z=2 5x-9y-3z=-10
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x+3y+4z=3x+5y+9z=25x-9y-3z=-10x+3y+4z=3x+5y+9z=25x-9y-3z=-10x+3y+4z=3x+5y+9z=25x-9y-3z=-10x+3y+4z=3x
x+3y+4z=3 x+5y+9z=2 5x-9y-3z=-10
x+3y+4z=3 x+5y+9z=2 5x-9y-3z=-10
x+3y+4z=3 x+5y+9z=2 5x-9y-3z=-10
x+3y+4z=3 x+5y+9z=2 5x-9y-3z=-10
x+3y+4z=3 ①
x+5y+9z=2 ②
5x-9y-3z=-10 ③
①-②得 -2y-5z=1 ④
5*①-③得 24y+23z=25 ⑤
-12*④-⑤得 37z=-37 z=-1
代入z到④,得y=2
代入y和z到①,得x=1
因此 x=1 y=2 z=-1
o(∩_∩)o
x+y=5 2x+3y-z=9 x-y+z=4
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
解方程组 x+y+z=5 2x-y-z=4 3x-2y-z=9
2x+3y-z=9,x+y+z=15,5x-4y-z=0
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y/2=z+x/3=y+z/4 x+y+z=27
三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13
x+2y=3x+2z=4y+z 求x:y:z
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
4X+9Z=12 {3Y-2Z=17X+5Z=4又4分之33X-Y+2Z=3{2X+Y-3Z=11X+Y+Z=66
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
六年级三元一次方程组.解下列方程组:(1)5x-3y+z=25x+2y-4z=3-5x+y-z=2(2)x-y-z=-13x_5y+7z=114x-y+2z=-1(3)9x-5y+z=-69x+y+4z=3-9x+3y-5z=0(4)x+y=22x+z=-27y+z=13