证明:x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2能被(x+y+z)整除证明:x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2是(x+y+z)的倍数

(Z-X)-4(X-Y)(Y-Z)=0 证明X-2Y+Z=0 ‘’是平方 证明x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2能被x+y+z整除 设x、y、z为整数,证明:x^4*(y-z)+y^4*(z-x)+z^4*(x-y)/(y+z)^2+(z+x)^2+(x+y)^2为整数 因式分解（证明）求证：(z-x)^2-4(y-z)(x-y)是一个非负数 证明:x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2能被(x+y+z)整除证明:x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2是(x+y+z)的倍数 (x-y)^2+4z(x-y)+4z^2 化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z} 已知x,y,z为正数,3^x=4^y=6^z,2x=py证明1/z-1/x=1/2y x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 数学--整式运算4(x-y+z)-2(x+y-z)-3(-x-y-z) 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z 集合X={x|x=2n-1,n属于Z},Y={y|y=4k+-1,k属于Z},证明X=Y. {(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y 证明方程x^4+y^4+Z^4=2x^2y^2+2y^2z^2+2z^2X^2+40无整数解 若(z-x)²-4(x-y)(y-z)=0,试证明:x+z=2y 已学至15.2乘法公式有不止一种解法. 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-x)=