计算1/6x-4y +1/6x+4y — 3x/4y^2-9x^2过程 ?答案希望是百分百的正确

计算：1/6x-4y+1/6x+4y-2y/4y^2-9x^2 计算.2x÷x/5x+3y^2-4y+4/2y-6·1/y+3÷12-6y/9-y^2 [(x+2y)(x-2y)+4(x-y)^2-6x]/(6x)计算 计算:(4xy(x-y)^-1+(x(y^-1)-(x^-1)y)/((x^-1)+(y^-1)))*(x+y)^-2 计算6x³y^6÷(1/2)y³÷(-3x²y)-(12x^4y^6-8x²y^4-16x³y^5)÷4x²y³ 计算：5x-2y-6+ (1/x) + (1/y) 计算1/6x-4y +1/6x+4y — 3x/4y^2-9x^2过程 ?答案希望是百分百的正确 1.计算1/6x-4y +1/6x+4y — 3x/4y^2-9x^2 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 计算：（3x-4y）-[-（2y+x）+（x-3y）]-6x 计算：[(x+2y)(x-2y)+4(x-y)^2]/6x 计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8) 计算1/6x-4y+2/4y^2-9x^2 计算(4x^2-2x^3+6x)/(-2x)-(x-1)^2y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/y-3) 已知x平方-6x+9与/y-1/互为相反数,计算(x/y-y/x)÷( x+y) 麻烦你们团队了：计算：1、（6xy^2-12x^3y^4+2x^2y^2)/(-2xy^2) 2、8(x-y)^4(x+y)^3/27[(x+y)(x-y)]^3 3(x+y)—4(x—y)=4 { (x+y)/2+(x—y)/6=1 2(x-y)/3—x+y/4=1 6(x+y)—4(2x-y)=16