lim[(3^x-1)sinx^3]/[ln(1+x^4)]在x趋于0的值

lim(1+sinx-sin(sinx))^x^-3 x趋于0 lim (x->0) 3x/(sinx-x) 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 极限函数计算lim( x^3 / sinx - x )lim( (1/e^x-1)-(1/x) ) lim e^3x-1/sinx,求值,x->0 lim x->0 (e^3x -1)/sinx = lim（x->无穷）sinx-tanx/e^x^3-1 lim((e^2-1-x)^2)/(x(sinx^3)) x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you lim(x->无穷大)3sinx/x= 求极限lim.tanx-sinx / x^3 lim(x->π/2)ln(3+sinx) lim(x-sinx)/x^3 x趋于0 不用洛必达法则～为什么不能这样做?=lim(1/x^2)-lim(sinx/x*1/x^2)=lim(1/x^2)-lim(1*1/x^2)=0 lim(tanx-sinx)/(sinx)3 1.lim sinX^3/(sinX)^3x→02.lim tan2X/sin5Xx→03.lim(1/1+x)^(1/2x+1)x→0 lim x趋于0[(tanx-sinx)/sinx^3]的极限 lim[x→0](tanx-sinx)/(sinx)^3=? lim(x→0)(sinx-tanx)/(sinx)^3