2x+3y+2z=10 3x+4y+z=11 4x+5y+z=12

2x+z=10 x+y-z=4 3x-y-z=0 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z {2x+y=10 {x-y+z=4 {3x-y-z=0 X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z X=3z X+y+z=12 X+2y-2z=10 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1 x+2y+3z=10,4x+3y+2z=15则x+y+z= x+2y+3Z=10,4x+3y+2z=15,求x+y+z=