x+2y+3z=10,4x+3y+2z=15则x+y+z=
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x+2y+3z=10,4x+3y+2z=15则x+y+z=x+2y+3z=10,4x+3y+2z=15则x+y+z=x+2y+3z=10,4x+3y+2z=15则x+y+z=x+2y+3z=104x+
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3z=10
4x+3y+2z=15
2式相加5x+5y+5z=25
x+y+z=5
因为 x+2y+3z=10,4x+3y+2z=15
两式子相加得到 5x+5y+5z＝25
则x+y+z＝5
加起来5x+5y+5z=10+15=25
x+y+z=5
因为 x+2y+3z=10。。。。1
4x+3y+2z=15。。。。。。2
所以 由1、2式子相加得 5x+5y+5z＝25
所以x+y+z＝25/5＝5
因为x+2y+3z=10,4x+3y+2z=15
所以x+2y+3z+4x+3y+2z=5x5y5z
把5提出来，则5（x+y+z)=25
SO:x+y+z=5
x+2y+3z=10
4x+3y+2z=15
2式相加5x+5y+5z=25
x+y+z=5
绝对正确
相信我
x+2y+3z+4x+3y+2z=25
5x+5y+5z=25
x+y+z=5
2x+z=10 x+y-z=4 3x-y-z=0
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
{2x+y=10 {x-y+z=4 {3x-y-z=0
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
X=3z X+y+z=12 X+2y-2z=10
x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少,
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x-y+4z=10,x+3y+2z=2,x+2y+3z=11.
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3Z=10,4x+3y+2z=15,求x+y+z=