x+y+z=4 2x+3y-z=6 3x+2y+2z=10
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x+y+z=42x+3y-z=63x+2y+2z=10x+y+z=42x+3y-z=63x+2y+2z=10x+y+z=42x+3y-z=63x+2y+2z=10X+Y+Z=4,2*(X+Y+Z)+X
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
X+Y+Z=4,
2*(X+Y+Z)+X=10,可以解出X=2.
套入第二个和第一个.4+3Y-Z=6 6+2Y＋2Z＝10
那么3Y=Z+2,2Y+2Z=4.
Y=1,X=1
X+Y+Z=4=2+1=1
2x+3y-z=6=4+3-1=6
3x+2y+2z=10=6+2+2
x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
2x+z=10 x+y-z=4 3x-y-z=0
x+y+z=6 x+2y+3z=14 y+1=z
三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6
x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少,
2x-y+2z=6 3x+y-3z=-4 x+y+z=6
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿
x+y-z=6,x-3y+2z=1,3x+2y-z=4
X+y-z=6;x-3y+2z=0;3x+2y-z=4
x+y-z=6 x-3y+2z=1 3x+2y-z=4
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}