求函数y=cos(x^2)·sin^2(1/x)的微分dy .

来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/31 07:31:52
求函数y=cos(x^2)·sin^2(1/x)的微分dy.求函数y=cos(x^2)·sin^2(1/x)的微分dy.求函数y=cos(x^2)·sin^2(1/x)的微分dy.y=cos(x^2)

求函数y=cos(x^2)·sin^2(1/x)的微分dy .
求函数y=cos(x^2)·sin^2(1/x)的微分dy .

求函数y=cos(x^2)·sin^2(1/x)的微分dy .
y=cos(x^2)·sin^2(1/x)
y'=-2xsin(x²)sin²(1/x)+cos(x²)2sin1/x cos1/x ·-1/x²
=-2xsin(x²)sin²(1/x)-1/x² cos(x²)sin2/x
所以
dy=【-2xsin(x²)sin²(1/x)-1/x² cos(x²)sin2/x】dx