sin^4a-cos^4a=sin^2-cos^2a
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sin^4a-cos^4a=sin^2-cos^2asin^4a-cos^4a=sin^2-cos^2asin^4a-cos^4a=sin^2-cos^2a运用平方差公式和恒等式sin²a+
sin^4a-cos^4a=sin^2-cos^2a
sin^4a-cos^4a=sin^2-cos^2a
sin^4a-cos^4a=sin^2-cos^2a
运用平方差公式和恒等式sin²a+cos²a=1
sin⁴a-cos⁴a=(sin²a+cos²a)(sin²a-cos²a)=sin²a-cos²a
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sin^4a-cos^4a
=(sin^2+cos^2a)(sin^2-cos^2a)
=sin^2-cos^2a
sin^4+sin^2cos^2+cos^2a=
(cos a)^4+(sin a)^2*(sin a)^2+(sin a)^2=?
cosA+cos^2A=1,sin^2A+sin^4A+sin^8A
sin^4a-cos^4a=sin^2a-cos^2a
证明sin^4a-cos^4a=sin^2a-cos^2a
tan a =3求4sin a-2cos a/5cos+3sin a
sin^4a-cos^4a=sin^2-cos^2a
=1-(sin^6a+cos^6a) ------(1)=1-(sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------(2)由(1)怎么能到(2)呢=1-(sin^6a+cos^6a)=1-(sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a)
Sin^4a-cos^4a=
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
求证1/sin^2a+3/cos^2a>=4+2根号下31/sin²a +3/cos²a=(sin²a+cos²a)/sin²a +3(sin²a+cos²a)/cos²a=1+cos²a/sin²a+3+3sin²a/cos²a=4+cos²a/sin²a+3sin²a/cos²a≥4+2√[(cos
8sin(45+a)sin(45-a)=1,sin^4a-cos^4a=
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
已知(4sin a-2cos a)/(5cos a +3sin a)=6/11,求cos^4 a-sin^4 a
已知sin a-2cos a=0 求4sin^2 a-3sin a x cos a-5cos^2 a的值
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
sin^6 a+cos^6 a+3sin^2 acos^2a=(sin^2 a+cos^2 a)(sin^4 a+cos^4 a-sin^2 acos^2 a)是如何计算出的