y=-10x²+110x+2100怎么化简

已知x²y²+x²+y²=10xy-16 求x,y 若x²+y²+4x-10y+29=0,则x²y+xy²= x²+y²-2x-6y+10=0 求分式x²-y²/xy xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 ( x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0 )求出x,y 已知x²-4x+y²-10y+29=0.求x²y²+2x³y²+[x²]²y²的值. 谁能帮我解这道二元二次方程,急5x²+10y² = 187.52x²+5y²= 4x²- y²+2.5 已知(x+y)²;=8,(x-y)²;=4,求x²+y² -a²-4b²+4ab=?(分解因式,1.-a²-4b²+4ab=?2.(x-y)²-10(x-y)+25=?3.(x²-1)²+6(1-x²)+9=?4.4(x+y)²-20(x+y)+25=?5.1/4x²+x+1=?6.(3x-5y)²+2(3x-5y)+1=?7.4(2x-y)²+24(2x-y)+36=?8.(2x-5)²+28x-21=?( 已知(x²+y²)(x²+y²-6)+9=0 ,求x²+y²的值. 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 若4x²+9y-12x+6y+10=0,则x²+y²= (x+y)²-10(x+y)+25 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0请帮忙算出这组方程的解. 求两圆C1:x²+y²-10x-10y=0,C2：x²+y²+6x+2y-40=0公共弦长 已知x²+4x+y²-10y+29=0 求【x+2y】÷【x²-2y²】的值