{2x+y+Z=10 {2x+4y+3z=9 {2x+2y+2=16{3x+2y+5z=11 {x+y+2z=8{5x+6y+7z=13
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{2x+y+Z=10{2x+4y+3z=9{2x+2y+2=16{3x+2y+5z=11{x+y+2z=8{5x+6y+7z=13{2x+y+Z=10{2x+4y+3z=9{2x+2y+2=16{3x
{2x+y+Z=10 {2x+4y+3z=9 {2x+2y+2=16{3x+2y+5z=11 {x+y+2z=8{5x+6y+7z=13
{2x+y+Z=10 {2x+4y+3z=9 {2x+2y+2=16{3x+2y+5z=11 {x+y+2z=8{5x+6y+7z=13
{2x+y+Z=10 {2x+4y+3z=9 {2x+2y+2=16{3x+2y+5z=11 {x+y+2z=8{5x+6y+7z=13
题目 应是
{2x+y+Z=10 (1)
{2x+4y+3z=9 (2)
{2x+2y+z=16 (3)
由(2)-(1)得
3y+2z=-1
由(3)-(1)得
y=6
z=-19/2
x=23
{3x+2y+5z=11 (1)
{x+y+2z=8 (2)
{5x+6y+7z=13 (3)
由(1)-(2)*2得
x+z=-5 (4)
由(3)-(2)*6得
x+5z=35 (5)
由(5)-(4)得
4z=40
z=10
x=-15
y=3
2x+z=10 x+y-z=4 3x-y-z=0
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
{2x+y=10 {x-y+z=4 {3x-y-z=0
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x-y+4z=10,x+3y+2z=2,x+2y+3z=11.
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3Z=10,4x+3y+2z=15,求x+y+z=
3x+2y+z=4 x+y+z=10 2x+3y-z=1
x+y+2z=5 2x-y-z=4 3x+y-3z=10