若tanα=2/3,则tan﹙2α-(π/4))=__?

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若tanα=2/3,则tan﹙2α-(π/4))=__?若tanα=2/3,则tan﹙2α-(π/4))=__?若tanα=2/3,则tan﹙2α-(π/4))=__?tan2α=2tanα/[1-(

若tanα=2/3,则tan﹙2α-(π/4))=__?
若tanα=2/3,则tan﹙2α-(π/4))=__?

若tanα=2/3,则tan﹙2α-(π/4))=__?
tan2α=2tanα/[1-(tanα)^2]
=2*2/3/(1-4/9)
=12/5
tan﹙2α-(π/4))=(tan2α-1)/(1+tan2α)
=(12/5-1)/(1+12/5)
=7/17