cos(π/3-2x)怎样化等于sin(2x+π/6)
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cos(π/3-2x)怎样化等于sin(2x+π/6)cos(π/3-2x)怎样化等于sin(2x+π/6)cos(π/3-2x)怎样化等于sin(2x+π/6)cos(π/3-2x)=cos(π/3
cos(π/3-2x)怎样化等于sin(2x+π/6)
cos(π/3-2x)怎样化等于sin(2x+π/6)
cos(π/3-2x)怎样化等于sin(2x+π/6)
cos(π/3-2x)=cos(π/3)
sin(2x+π/6))=sin(π/6)
因为cos(π/3)=sin(π/6)
所以cos(π/3-2x)=sin(2x+π/6)
另一种解法:
cos(π/3-2x) 根据公式 cosx=sin(π/2-x) 得
=sin[π/2-(π/3-2x)]
=sin[(π/2-π/3)+2x]
=sin(2x+π/6)
cos(π/3-2x)
=sin[π/2-(π/3-2x)]
=sin[(π/2-π/3)+2x]
=sin(2x+π/6)
一个角的余弦值等于它的余角的正弦值
或者说
两角互余,一个角的余弦值等于另一个角的正弦值
cos(π/3-2x)=cos[(π/2-(2x+π/6)]=sin(2x+π/6)
cos(π/3-2x)
=cos[2π-(π/3-2x)]
=cos(2x+5π/3)
=cos[π+(2x+2π/3)]
=-cos(2x+2π/3)
=-cos(π/2+2x+π/6)
=sin(2x+π/6)
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