1^2+2^2+3^2+…+(n-1)^2+n^2=?
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1^2+2^2+3^2+…+(n-1)^2+n^2=?1^2+2^2+3^2+…+(n-1)^2+n^2=?1^2+2^2+3^2+…+(n-1)^2+n^2=?n(n+1)(2n+1)/6数学归纳法
1^2+2^2+3^2+…+(n-1)^2+n^2=?
1^2+2^2+3^2+…+(n-1)^2+n^2=?
1^2+2^2+3^2+…+(n-1)^2+n^2=?
n(n+1)(2n+1)/6
数学归纳法证明
n(n+1)(2n+1)/6
数学归纳法证明
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