[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简

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[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简原

[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简

[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
原式=(3n²+3n+2n²-3n²+n+6n²+12n)/6
=(2n²+6n²+16n)/6
=(n²+3n+8)/3