[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/21 22:38:17
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简原
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
原式=(3n²+3n+2n²-3n²+n+6n²+12n)/6
=(2n²+6n²+16n)/6
=(n²+3n+8)/3
证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
2^n/n*(n+1)
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简(n+1)(n+2)(n+3)
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n
(n+2)!/(n+1)!
判断 当n>1时,n*n*n>3n.( )
lim2^n +3^n/2^n+1+3^n+1
n(n+1)(n+2)(n+3)+1 因式分解
n(n+1)(n+2)(n+3)+1等于多少
3(n-1)(n+3)-2(n-5)(n-2)
lim(n+3)(4-n)/(n-1)(3-2n)
lim(n^3+n)/(n^4-3n^2+1)
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(2^n+3^n)^1
(n趋向无穷)