∫cos(x^2)dx=?如果 3^2=3*3=9,7^2=7*7=49,X^2=X*X.那么∫SIN(X^2)dx=?

∫(2/cos^2x)dx= ∫cos(x+2)dx=多少 ∫sin^3(x)cos^2(x)dx= ∫cos((x/3)-1)dx=? 不定积分cos(x^1/2)dx=? ∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = ∫cos(2x+1)^5dx=? cos(x^2)dx 微积分1/cos^2(x)dx=?微积分1/cos^2(x)dx＝? ∫cos(x^2)dx=?如果 3^2=3*3=9,7^2=7*7=49,X^2=X*X.那么∫SIN(X^2)dx=? 定积分∫(-π/2,π/2)(cos^4x+sin^3x)dx= ∫ 1/2cos(x/2)dx=?x>π/3 ∫ 1/2cos(x/2)dx=?x>π/3 求解 ∫sin(6x)^3*cos(6x)^8 dx=? 范围[pi/2,0] ∫x* cos²x dx=? ∫cos(x*x)dx=? ∫x*(cos^2x)dx