limx->1求极限(x/x-1 - 1/lnx)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 17:46:17
limx->1求极限(x/x-1-1/lnx)limx->1求极限(x/x-1-1/lnx)limx->1求极限(x/x-1-1/lnx)lim(x->1)[x/(x-1)-1/lnx]=lim(x-
limx->1求极限(x/x-1 - 1/lnx)
limx->1求极限(x/x-1 - 1/lnx)
limx->1求极限(x/x-1 - 1/lnx)
lim(x->1)[ x/(x-1) - 1/lnx ]
=lim(x->1) [xlnx-(x-1)]/[(x-1)lnx] (0/0)
= lim(x->1) [ (1+lnx-1) / (lnx + (x-1)/x) ]
= lim(x->1) [ xlnx/(xlnx+(x-1) ] (0/0)
= lim(x->1) [ (lnx+1)/(x+1+1) ]
=1/2
limx->1 (x/x-1 - 1/lnx)
=limx->1 (xlnx-x+1)/[(x-1)lnx] (0/0)
=limx->1 lnx/[lnx+(x-1)/x]
=limx->1 xlnx/[xlnx+(x-1)] (0/0)
=limx->1 (lnx+1)/[lnx+2]
=1/2
求极限:limx^(x^x-1),x趋向于0+
limx->1求极限(x/x-1 - 1/lnx)
limx->1 sin(x-1)/x-1 求极限
limx趋向1 2x+3/x-1 求极限
求极限limx→+∞[x^(1/x)*(1-lnx)],
limx(e^(1/x)-1) x趋于∞,求极限
求极限limx→1 x/(x-1)
limx→∞(1-1/2x)^x求极限
求极限limx趋向0+[x^ln(1+x)]
求极限 limx→0=(1/X)^(tan x)
limx→∞ x/x+1求极限
求极限limx→0ln(1+x)/2x
limx→∞ (1+2/x)^(x+3)求极限
limx→1,lnx/x-1用洛必达法则求极限
求极限,limx~0 (1-x)^(1/-sinx)
limx ln(1+1/x^2) 求极限?
limx→0(1/sinx-1/x)求极限
极限limx→1负 lnxln(1-x)求过程