计算x/(y+z)=y/(x+y+1)=z/(x+y-1)的值同上.说得清楚详细些,千万千万不要跳步骤,反正要让我看得懂.答案上是1/2和-1好象要分类讨论的,什么当x+y+z=0时,x+y+z≠0时,
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计算x/(y+z)=y/(x+y+1)=z/(x+y-1)的值同上.说得清楚详细些,千万千万不要跳步骤,反正要让我看得懂.答案上是1/2和-1好象要分类讨论的,什么当x+y+z=0时,x+y+z≠0时
计算x/(y+z)=y/(x+y+1)=z/(x+y-1)的值同上.说得清楚详细些,千万千万不要跳步骤,反正要让我看得懂.答案上是1/2和-1好象要分类讨论的,什么当x+y+z=0时,x+y+z≠0时,
计算x/(y+z)=y/(x+y+1)=z/(x+y-1)的值
同上.
说得清楚详细些,千万千万不要跳步骤,反正要让我看得懂.
答案上是1/2和-1
好象要分类讨论的,什么当x+y+z=0时,x+y+z≠0时,
计算x/(y+z)=y/(x+y+1)=z/(x+y-1)的值同上.说得清楚详细些,千万千万不要跳步骤,反正要让我看得懂.答案上是1/2和-1好象要分类讨论的,什么当x+y+z=0时,x+y+z≠0时,
设x/(y+z)=y/(x+y+1)=z/(x+y-1)=k
则有x=k(y+z)
y=k(x+y+1)
z=k(x+y-1)
三式相加得(x+y+z)=2k(x+y+z)
所以 k=1/2
也就是x/(y+z)=y/(x+y+1)=z/(x+y-1)=k=1/2
我考虑到这一点了,不好意思没写.补充如下:当x+y+z=0时,y+z=-x
x/(y+z)=y/(x+y+1)=z/(x+y-1)=x/(y+z)
=x/(-x)=-1
综上得到x/(y+z)=y/(x+y+1)=z/(x+y-1)=1/2或-1
计算x/y+x=y/x+z+1=z/x+y-1的值
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(x+y-z)(x-y+z)=
计算(x+y-z)(x-y-z)
计算:(x-y+z)(-x+y+z)
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
x y=21 z y=24 x y z=32如何计算
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
{x+y-z=11 y+z-x=5 z+x-y=1
{x+y-z=11,x-y-z=-5,x-y+z=1
x=y; y=z; z=x/y
分式加减的几道题目求速度1 .(x+y)²/(x-z)(y-z) - (y+z)²/(x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y=
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计算(x+y+z)(-x+y+z)(x-y+z)(x+y-z)
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z+=x>y?++x: