2x+y=10 4y+2=21 5x-z=10 求xyz的值,此题怎么解啊

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x-y-2z=10 y-3z=-4 3x-y+5Z=21 三元一次方求大神x-y-2z=10y-3z=-43x-y+5Z=21 X-Y-Z=0 X+Y-3Z=4 2X-5Y+7Z=21 -2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10 x+y+2z=5 2x-y-z=4 3x+y-3z=10 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31 方程组{x/2+y/3-z=-5,x/3-y/2+z/2=10,x/2-y/3-z/4=6,求x,y,z x+y-2z=5 2x-y-z=4 3x+y-3z=10；分别求x、y、z的值. 已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 2x+z=10 x+y-z=4 3x-y-z=0 {2x+y=10 {x-y+z=4 {3x-y-z=0 x+y=5 2x+3y-z=9 x-y+z=4 {x+y+z=12 x+2y+5z=22 x=4y 6x-y-z=3 2x-4y+8z=5 3x-6y-z=10 y z 分别等于几?大虾