limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 13:39:51
limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5limn趋向无穷大(4x^2-3)^3(3x-2
limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
分子分母同除以x^10
lim(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
=lim(4-3/x^2)^3(3-2/x)^4/(6+9/x^2)^5
=4^3*3^4/6^5
=2/3
limn趋向无穷大(4x^2-3)^3(3x-2)^4/(6x^2+9)^5
limn趋向无穷大(2^(n+1)-3^n)/(3^(n+1)+2^n)=?
数列极限定义证明limn^(2/3)sinn/(n+1)=0,n趋向于无穷大,马上求解
limn^2(1-cosπ/n),n趋向无穷大
limx趋向无穷大,(1+1/x)^3x+2=?
lim(x^3+1)(3+cosx)/2x^4-1(x趋向无穷大)的极限
limn趋向正无穷大.n-1/2n+1的极限是
limx趋向无穷大 2^x
求极限:当X趋向无穷大时 [ln(2^x+3^x)]/[ln(3^x+4^x)]
1.lim x趋向于无穷大sinx/x+1=? 2.lim x趋向于无穷大(1+2/x)^x+3=?
用极限定义证明x趋向无穷大方程(x^2-1)/(4x^2-7x+3)=1/4
lim(x-3/x+1)^x lim趋向无穷大
limn趋向于无穷 (n+3/n+1)^n/2=?
limn趋于无穷大时,[2*(3^n)+3*((-2)^n)]/3^n的极限
请问当x趋向无穷大时,(2x+1)/(3x-4)的极限,答案是2/3.
求极限lim[(x-4)/(x+3)]^x x趋向无穷大
lim[(x-4)/(x-3)]^x x趋向无穷大 求极限
x趋向无穷大时求lim√(x^2-3x+1)/x极限