a,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号ac

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a,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号aca,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号aca,b,c为正实数,

a,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号ac
a,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号ac

a,b,c为正实数,求证1/a+1/b+1/c>=1/根号ab+1/根号bc+1/根号ac
a,b,c为正实数,所以:
1/a+1/b>=2根号1/ab
1/a+1/c>=2根号1/ac
1/b+1/c>=2根号1/bc
以上三式相加得:
2(1/a+1/b+1/c)>=2[1/根号ab+1/根号bc+1/根号ac]
即:1/a+1/b+1/c>=1/根号ab+1/根号ac+1/根号bc