求极限lim(x→0) sin(1-x)/(1-x^2)
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求极限lim(x→0)sin(1-x)/(1-x^2)求极限lim(x→0)sin(1-x)/(1-x^2)求极限lim(x→0)sin(1-x)/(1-x^2)如果x是趋于0的,那极限值就是sin1
求极限lim(x→0) sin(1-x)/(1-x^2)
求极限lim(x→0) sin(1-x)/(1-x^2)
求极限lim(x→0) sin(1-x)/(1-x^2)
如果x是趋于0的,那极限值就是sin1
估计题目是x趋于1的吧?
如果x是趋于1的 可以用等价无穷小 sin(1-x)~(1-x)
原极限=lim(x→1) 1/1+x =1/2
lim(x→0) sin(1-x)/(1-x^2)
=lim(x→0) sin(1-x)/[(1-x)(1+x)]
=lim(x→0) 1/(1+x)
=1lim(x→0)sin（1-x）=0不是才能用lim(x→0)sinx/x=1吗x->0
x ~ sinx
sin(1-x) ~ 1-x不懂 明白点By Taylo...
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lim(x→0) sin(1-x)/(1-x^2)
=lim(x→0) sin(1-x)/[(1-x)(1+x)]
=lim(x→0) 1/(1+x)
=1
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