求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]}
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/31 01:20:37
求极限lim(x→0){x[sin(1/x^2)-1/sin2x]}求极限lim(x→0){x[sin(1/x^2)-1/sin2x]}求极限lim(x→0){x[sin(1/x^2)-1/sin2x
求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]}
求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]}
求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]}
xsin(1/x^2)-x/sin2x
1/x^2→∞,所以sin(1/x^2)在-1到1之间震荡
而x→0,所以xsin(1/x^2)极限是0
x/sin2x=(1/2)*(2x)/sin2x
x→0则2x→0
所以2x/sin2x极限是1
所以原式极限=0-1/2=-1/2
求极限,lim x趋于0 x * sin 1/x
求极限lim(x-->0)x^2 sin(1/x),
lim x->0(sqrt(sin(1/x^2)) 求极限
求极限 ((sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1
求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0
求极限lim(x→0) sin(1-x)/(1-x^2)
求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]}
求极限:lim x→0 ln[1+sin^2(x)]/[e^(x^2)-1]
lim x→0 (x∧2 cscx sin(1/x)) 求极限
求极限ln(1+2x)/sin(1+2x),lim x->0求它极限.
求极限~lim(x→0)[(1+xsinx)^1/2-cosx]/sin^2(x/2)
求极限x→0 lim(√2-√1+cosx)/sin^2x
求极限lim(x→∞)(sin√x+1-sin√x)
求极限lim(x→+∞)(sin√(x+1)-sin√x)
求极限lim(x趋于0时)sin(sinx)/x
求极限 lim (x->0) sin(sinx)/x
求极限lim(x-->0) (tanX-sinX)/[(sin^3)X]
求极限:lim(x*sin(1/x))^2