(2m+n-p)(2m-n+p)
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(2m+n-p)(2m-n+p)(2m+n-p)(2m-n+p)(2m+n-p)(2m-n+p)=[2m+(n-p)][2m-(n-p)]=4m²-(n-p)²=4m²-
(2m+n-p)(2m-n+p)
(2m+n-p)(2m-n+p)
(2m+n-p)(2m-n+p)
=[2m+(n-p)][2m-(n-p)]
=4m²-(n-p)²
=4m²-n²+2pn-p²
(2m+(n-p))(2m-(n-p))=2m*2m-(n-p)(n-p)=4m^2-n^2+2mp-p^2
原式=[2m+(n-p)][2m-(n-p)]
=4m²-(n-p)²
=4m²-n²+2pn-p²
（m-2n-p)(m-2n+p)-(m+2n+p)(m+2n+p)
化简,1.[(m+n-p)(m+p+n)-(m+n)²]/(-p),2.[(m+n)(m-n)-(m-n)²+2n(m-n)]/4n
化简(-m+2n-p)(-p-2n+m)
(2m+n-p)(2m-n+p)
(2m+n-p)(2m-n-p)等于什么
（2m+n-p）（ 2m+p-n）
(m-2n-p)(-m-2n-p)
化简:(2m+n-p)*(2m-n+p)
(-2m-3n-p)(2m-3n-p)
(m-2n+3p)(m+3n+3p)
因式分解：(m-n)(p-q)-(n-m)^2(q-p)
(2m+n-p)²
m-（2m-n-p）=
（m+n)-( )=2m-p
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
已知m、n、p满足|2m|+m=0,|n|=n,p|p|=1.化简：|n|-|m-p-1|+|p+n|-|2n+1|.已知m、n、p满足|2m|+m=0，|n|=n，p|p|=1.化简：|n|-|m-p-1|+|p+n|-|2n+1|.
n/m与2n+q/m+p,怎么通分
已知m、n、p满足/2m/+m=0,/n/=n,p/p/=1,化简/n/-/m-p-1/-/2n+1/.