化简cos^2B+cos^2(2/3Π-B) 答案是1-1/2sin(2B-Π/6)
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化简cos^2B+cos^2(2/3Π-B)答案是1-1/2sin(2B-Π/6)化简cos^2B+cos^2(2/3Π-B)答案是1-1/2sin(2B-Π/6)化简cos^2B+cos^2(2/3
化简cos^2B+cos^2(2/3Π-B) 答案是1-1/2sin(2B-Π/6)
化简cos^2B+cos^2(2/3Π-B) 答案是1-1/2sin(2B-Π/6)
化简cos^2B+cos^2(2/3Π-B) 答案是1-1/2sin(2B-Π/6)
cos²B+cos²(2/3Π-B)
=1/2(cos2B+1)+1/2[cos(4/3Π-2B)+1]
=1+1/2[cos2B+cos(4/3Π-2B)]
=1+1/2[2cos2/3Πcos(2B-2/3Π)]
=1-1/2cos(2B-2/3Π)
=1-1/2sin(2B-Π/6)
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
化简cos²B+cos²(2π/3-B)
化简cos(a+b)cos(a-b)+sin^2b
化简:2cos(A+B)cosB-cos(2A+B)
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
化简sin^2acos^b-cos^2asin^2b+cos^a-cos^2b
化简:cosα+cos(2π/3-α)+cos(2π/3+α)
化简cosθ+cos(θ+2π/3)+cos(θ+4π/3)
若COS(A+B)COS(A-B)=1/3,则COS^2A-COS^2B=多少
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
化简cos^2B+cos^2(2/3Π-B) 答案是1-1/2sin(2B-Π/6)
求和:cos(0)+cos(α)+cos(2α)+cos(3α)+……cos(nα)
已知A+B=2/3π,则cos^2A+cos^2B的最大值
已知cos(a+b)=4/5,cos(a-b)=-4/5,3π/2
.已知Cos(a+b)=4/5,cos(a-b)= -4/5,3/2π