1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和
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1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和1/3+
1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和
1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和
1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和
=1/(3*1)+1/(5*3)+.+1/(2^n+1)(2^n-1)
=(1/1-1/3)/2+(1/3-1/5)/2+.+[1/(2^n-1)-1/(2^n+1)]/2
=[1/1-1/3+1/3-1/5+...+1/(2^n-1)-1/(2^n+1)]/2
=[1/1-1/(2^n+1)]/2
=[2^(n-1)]/[2^n+1]
1/2(1-1/3+1/3-1/5+...+1/(2^n-1)-1/(2^n+1))=1/2(1-1/(2^n+1))
1/3+1/15+1/35+1/63+1/99+1/145+1/195+1/255
计算1/3+1/15+1/35+1/63+1/99+1/143+1/195+255+1/323+1/399
1/3+1/15+1/63+1/255+1/1023+--+1/(2^n+1)(2^n-1)求和
1,3,7,15 ( ) ( ）127 ．．．． 规律15，31，63( ) .255 规律
1/3＋1/15＋1/35＋1/63＋1/99＋1/143＋1/195＋1/255 +1/323+1/399=
1,3,7,15,31,63,127,255,511,1023的第N个是多少?
1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256
3分之1+15分之1+35分之1+63分之1+99分之1+143分之1+195分之1+255分之1简便运算怎么做?
1/3＋ 1/15＋ 1/35 ＋1/63 ＋ 1/99＋ 1/143＋ 1/195＋ 1/255的值是多少啊
1/3＋ 1/15＋ 1/35 ＋1/63 ＋ 1/99＋ 1/143＋ 1/195＋ 1/255的值是?
这条题怎么解?1/3+1/15+1/35+1/63+1/99+1/143+1/195+1/255用简便方法运算
1 3 15 255的排列规律
(1-1/15)+(1-1/35)+(1-1/63)+(1-1/99)+(1-1/143)+(1-1/195)+(1-1/255)+(1-1/323)
4/3+31/15+106/35+253/63...+2041/255找找规律 1又1/3+2又1/15+3又1/35+4又1/63+...8又1/255求高手解答
3/1+4/3+8/7+16/15+32/31+64/63+128/127+256/255怎么算?
计算 1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256
1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256用裂项解
简便计算：1/2+3/4+7/8+15/16+31/32+63/64+127/128+255/256