设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则a+b=几,

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设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则a+b=几,设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则

设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则a+b=几,
设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则a+b=几,

设a,b都是钝角,tana=√3(1+m),tan(-b)=√3(tana·tanb+m),则a+b=几,
tana=√3(1+m)
tana-√3=√3m
tanb=-√3tana·tanb-√3m
tanb=-√3tana·tanb-tana+√3
(tana+tanb)/(1-tana·tanb)=√3
tan(a+b)=√3
∵a,b都是钝角
∴a+b=240度