(tanx-sinx)/sin(x^3)的极限怎么求?如题

化简{sin(π+x)}/1+cos(3π-x)根号下(tanx-sinx)/(tanx+sinx) 求极限lim(x-->0) (tanX-sinX)/[(sin^3)X] limx→0 tan(tanx)-sin(sinx)/x^3 limx趋近于0 (tanx-sinx)/sin^3x lim(x->0)sin[sin(sinx)]/tanx=? limx→0 (tanx-sinx)/sin^3x =limx→0 (tanx-sinx)/x³ 为什么可以直接去掉sinx 已知sinx+cosx/sinx-cosx=3,求tanx,2sin^2x+(sinx-cosx)^2的值 已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)²的值 (tanx-sinx)/x^2sin^2x 极限x--->0 tanx=2求sinx/sin^3(x)-cos^3(x)的值 证明sin^3x(1+cotx)+cos^3x(1+tanx)=sinx+cosx 3sinX=sin(2X+Y) 求证：tan(X+Y)=2tanX 证明tanx-sinx/sin^3(x)=1-cosx/cosxsin^2(x) 求 (tanx-sinx)/(sin^3 x) 当x→0时的极限 求x趋近于0,(tanx-sinx)/(sin^3)x的极限 若tanx=-2分之一,求2sin^2x+sinx乘cosx-3cos^x 已知tanx=1/2,求sin x-cos x/2sinx+3cosx的值 求化简(sinx+tanx)/cos^2x+sin^2x+cosx