[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/24 21:17:10
[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域∑=[3+(-1)^n]^
[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域
[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域
[3+(-1)^n]^n*x^n/n幂级数收敛半径和收敛域
∑=[3+(-1)^n]^n*x^n/n
=∑|an|*x^n {|an|=[3+(-1)^n]^n/n}
1/Rn=lim(n->∞)|a(n+1)/an|
=lim(n->∞)|{[3+(-1)^(n+1)]^(n+1)/(n+1)}/{[3+(-1)^n]^n/n}|
当n取奇数时,
1/Rn=lim(n->∞)|{[3+1]^(n+1)/(n+1)}/{[3-1]^n/n}|
=lim(n->∞)|{2^(2n+2)/(n+1)}/{2^n/n}|
=lim(n->∞)|{2^(n+2)*n/(n+1)}|
=lim(n->∞)|{2^(n+2)/(1+1/n)}|
=∞
∴收敛半径为R=0,
x=0时,级数收敛于0,故收敛域为0点
当n取偶数时,
1/Rn=lim(n->∞)|{[3-1]^(n+1)/(n+1)}/{[3+1]^n/n}|
=lim(n->∞)|{2^(n+1)/(n+1)}/{2^(2n)/n}|
=lim(n->∞)|{2n/[2^n*(n+1)]}|
=lim(n->∞)|{2/[2^n*(1+1/n)}|
=0
∴收敛半径为R=∞,级数发散
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
幂级数[(-1)^n/3^n]x^n (|x|
判断 当n>1时,n*n*n>3n.( )
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
若(x^2+1/x)^n(n∈N+,n
设集合M={x|x=2n+1,n∈N},N={x|x=3n,n∈N},则M∩N=
n
n
n
n
(4x^n-2x^n-1-3x^n+2)÷(-5x^n-1)
计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1)
x^n-1(3x^n+4x^n+1-5x^n+2)
x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x
∞∑ n=1 [(2n-1)/(3^n)]*[x^(2n-2)] ∞∑ n=1 [((-1)^n)/(2n-1)*(x^(2n)
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简