log8(9)除以log2(3)中间有点不太熟悉啊。

log8(9)除以log2(3)中间有点不太熟悉啊。 log8(9)*log2(3) log8的27除以log2的3 (log8 9/log2 3)=? 求(log2^3+log8^9) log8 9除以log2 3是多少（注意9在8上,3在2上） log8ˇ9除以log2ˇ3 等于?ˇ为上标符号 log8^9/log2^3的值是 已知log2^3=a.则log8^3= log8^9= 求值:log8(底数)9/log2(底数)3 (过程） log8的9次方/log2的3次方= 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 ( log8^9 )/( log2^3 )求值其中2和8是底数 3和9是真数 (log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))