lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/04 01:14:52
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y=limx^2/2^x+limy^2/2^y=lim[2x/(ln2*2^x)]+lim[2y/(ln2*2^y)]=lim2/[(in2)^2*2^x]+lim2/[(in2)^2*2^y]=0
lim(x,y都趋向无穷大)x^2/2^x+y^2/2^y为什么为0?
lim(x/(1+x^2)),x趋向无穷大
求lim(x+y)/(x*x+y*y),x和y都趋向无穷大时的极限
lim(x趋向无穷大)[1+2/(x+2)]^(x+2)
lim x趋向无穷大 (1+2/x)^x=?
lim(x-3/x+1)^x lim趋向无穷大
lim 根号(x+2)(x-1) 减去x的极限(x趋向正无穷大)
幂指函数求极限 lim x趋向无穷大(x-3/x+2)^x=
求lim(1-(2/x))^(-x)的极限,x趋向无穷大
求极根题目(高数)求极限lim(x趋向无穷大)(1+2/x)^-x
lim(1+1/x^2)^x x趋向于无穷大的极限
求极限 lim(x趋向于无穷大) x{ln(2+1/x)-ln2} 要详解
lim(x-1分之x+2)的平方,x趋向无穷大
高等数学[函数极限]lim(x趋向正无穷大)x*sin 2/x
极限求解lim[(2/π)arctanx]^x (x趋向于正的无穷大)
证明:lim(cosX/X^2)=0 (X趋向无穷大)
证明极限不存在lim (x 和y)趋向于无穷大 (x^2-5y^2) / (x^2+3y^2) 证明该极限不存在
lim x/(x+sinx)x趋向无穷大 怎么求