数列{an}满足a1=3/2,a(n+1)=an^2-an+1 (n∈N*),则m=(1/a1)+(1/a2)+……(1/a2009)的整数部分是A.0 B.1 C.2 D.3
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 04:09:35
数列{an}满足a1=3/2,a(n+1)=an^2-an+1(n∈N*),则m=(1/a1)+(1/a2)+……(1/a2009)的整数部分是A.0B.1C.2D.3数列{an}满足a1=3/2,a
数列{an}满足a1=3/2,a(n+1)=an^2-an+1 (n∈N*),则m=(1/a1)+(1/a2)+……(1/a2009)的整数部分是A.0 B.1 C.2 D.3
数列{an}满足a1=3/2,a(n+1)=an^2-an+1 (n∈N*),则m=(1/a1)+(1/a2)+……(1/a2009)的整数部分是
A.0 B.1 C.2 D.3
数列{an}满足a1=3/2,a(n+1)=an^2-an+1 (n∈N*),则m=(1/a1)+(1/a2)+……(1/a2009)的整数部分是A.0 B.1 C.2 D.3
a(n+1)-1=an*(a(n)-1),1/(a(n+1)-1)=1/[an*(a(n)-1)=1/(an-1)-1/an
得1/(an-1)-1/(a(n+1)-1)=1/an,通过累加的方法得,
1/a1+1/a2+……+1/a2009= 1/(a1-1)-1/(a2010-1)=2-1/(a2010-1)
由a(n+1) - an=(an-1)^2≥0 ,即a(n+1)≥an, 由a1=3/2,得a2=7/4,得a3=2又5/16.
所以,a2010≥a009≥a2008≥……≥a3>2,即 0
数列[An]满足a1=2,a(n+1)=3an-2 求an
数列{an}满足a1=3,a n+1=2an,则a4等于
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
数列{An}满足A1=1,A(n+3)=An+3,A(n+2)=An +2
已知数列{an}满足a(n+1)=an+3n+2,且a1=2,求an=?
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an
已知数列an满足a(n+1)=an+3n+2,且a1=2,求an
已知数列{an}满足条件a1=3,且a( n+1)-an=(20)^n+n,求通项公式已知数列{an}满足条件a1=3,且a( n+1)-an=(2)^n+n,求通项公式
已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=?
设数列an满足a1=2,a(n+1)=3an+2^(n-1),求an2,设数列an满足a1=2,a(n+1)=3an+2n,求an
数列an满足a1=1/3,Sn=n(2n-1)an,求an
数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足a1=1,a2=3,a(n+2)=a(n+1)-an,求S2012
(1)数列{an}中,a1=1,a2=-3,a(n+1)=an+a(n+2),则a2005=____(2)已知数列{an}满足a1=1,a1×a2×a3…an=n^2,求an.
已知数列{an}满足3a(n+1)=2an-4,且a1=1/5,求an
已知数列{an}满足:a1=1,an=a1+2a2+3a3+``````+(n-1)a(n-1)(n大于等于2),则通项公式an是什么?
数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5,求数列{an}的通项公式