等差数列{an}满足a1+a2+a3+…a101=0,则有
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 18:03:49
等差数列{an}满足a1+a2+a3+…a101=0,则有等差数列{an}满足a1+a2+a3+…a101=0,则有等差数列{an}满足a1+a2+a3+…a101=0,则有a101=a100+d=a
等差数列{an}满足a1+a2+a3+…a101=0,则有
等差数列{an}满足a1+a2+a3+…a101=0,则有
等差数列{an}满足a1+a2+a3+…a101=0,则有
a101=a100+d=a99+2d=```=a1+100d
a1+a2+a3+…a101=a1+(a1+d)+(a1+2d)+```(a1+100d)=101a1+5050d=0
a1+50d=0
a1=-50d
即a51=0
a51=0
等差数列{an}满足a1+a2+a3+…a101=0,则有
已知a1+a5=8,a2·a3=2,求通项公式an等差数列
等差数列中a1.a2.a3.a4.a1+a2=a3+a4?
已知等差数列{an}满足a1+a2+a3+……+a99=0则( ) A.a1+a99>0 B.a已知等差数列{an}满足a1+a2+a3+……+a99=0则( )A.a1+a99>0 B.a1+a99
等差数列[an]中,若a1+a3+a5=-1则a1+a2+a4+a5=
已知数列{an}满足a1=1,an=a1+1/2a2+1/3a3+…+1/(n-1)an
等差数列an公差不等于0且a1,a3,a9成等比数列,求(a1+a3+a9)除(a2+a4+a10)
已知数列{an}和{bn}满足关系:bn=(a1+a2+a3+…+an)/n,(n∈N*).若{bn}是等差数列,求证{an}为等差数列
已知an为等差数列,a1+a3+a5=105,a2+a4+a6=99,求a20
等差数列an中 a1+a4=39 a2+a5=35 则a3+a6=
已知等差数列{an}满足a1+a2+a3+……+a101=0,则有()A.a1+a101>0 B.a2+a100
等差数列an满足a1+a2+...+a101=303 则a3+a99=
已知等差数列{an}满足a1+a2+a3+...+a11=0,则有A、a1+a11>0B、a2+a10
数列{an}{bn}满足bn=a1+2a2+3a3+…+nan/(1+2+3+…+n),若数列{an}为等差数列,求证;{bn}为等差数列.
等差数列an,若a1+a2+a3.+a1000 B、a3+a98
设数列{an}满足:a1+a2/2+a3/3+a4/4……+an/n=An+B,其中A、B为常数.数列{an}是否为等差数列?
an是等比数列,a1+a2+a3=7,a1*a2*a3=8,求an?
已知数列{an}为等比数列a1+a2+a3=21 a1×a2×a3=216 求an