化简求值cos(-11π/3)=_,tan(-1035°)=_
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 13:47:24
化简求值cos(-11π/3)=_,tan(-1035°)=_化简求值cos(-11π/3)=_,tan(-1035°)=_化简求值cos(-11π/3)=_,tan(-1035°)=_cos(-11
化简求值cos(-11π/3)=_,tan(-1035°)=_
化简求值cos(-11π/3)=_,tan(-1035°)=_
化简求值cos(-11π/3)=_,tan(-1035°)=_
cos(-11兀/3+4兀)=cos(兀/3)=0.5
tan(-1035°)=tan(-3x360°+45)=tan45°=1
cos(-11π/3)=1/2 tan(-1035°)=tan(-3x360°+45)=tan45°=1
化简求值cos(-11π/3)=_,tan(-1035°)=_
COS(π/7)+COS(3π/7)+COS(5π/7)化简求值,
求值:cos(arcsin1/3)=
已知cosα=√3/3,化简并求值:(1+(tan2α)^2)[cos(2α+π/3)+cos(2α-π/3)]
求数学高手帮忙cos(2π/7)+cos(4π/7))+cos(6π/7)=?(化简求值)
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
化简求值cos(π/7)cos(2π/7)cos(4π/7)
求值!=_=
求值:sin(26π/3)+cos(-17π/4)=
cos(-pai-a) 化简求值
求值化简:sinα*cosα
cos(3π/2 - π/3),求值
cos(-8π/3)求值
cos(-8π/3)求值
求值:cos(arcsin√3/2)=
求值:cos(arcsin1/3)
求cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)(5/24)(11/24)=5/11?,而且过程和题好像都没关系。