3x+2y+z=14 { x+y+z=10 2x+3y-z=1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 15:50:03
3x+2y+z=14{x+y+z=102x+3y-z=13x+2y+z=14{x+y+z=102x+3y-z=13x+2y+z=14{x+y+z=102x+3y-z=1①3x+2y+z=x+y+z+2
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
①3x+2y+z=x+y+z+2x+y=10+2x+y=14,即2x+y=4,y=4-2x.
②由2x+3y-z=1得:3y=1+z-2x=3(4-2x).整理后得:z=11-4x.
③把①和②中的y和z代入原式,得:x=1,y=2,z=7.
④代入原式验算:3×1+2×2+7=14,验算正确.
x=1
y=2
z=7
x=1
y=2
z=7
x+y+z=6 x+2y+3z=14 y+1=z
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
(1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1.
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
[3x+2y+z=14,x+y+z=10,2x+3y-z=1]
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
3x+2y+z=14 x+y+2z+-3 2x+3y-z=1
解方程:x+z=y (1) ,7z-(x+y)=2 (2) ,x+y+z=14 (3)
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y
分式加减的几道题目求速度1 .(x+y)²/(x-z)(y-z) - (y+z)²/(x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y=
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0