2X+2Y+Z=4 X+4Y+3Z=6 X+3Y+2Z=7

x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 3x-y+z=4,2z+3y-z=12,x+y+z=6的解 2x+z=10 x+y-z=4 3x-y-z=0 三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 2x-y+2z=6 3x+y-3z=-4 x+y+z=6 x+y+z=4 2x+3y-z=6 3x+2y+2z=10 x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿 x+y-z=6,x-3y+2z=1,3x+2y-z=4 X+y-z=6;x-3y+2z=0;3x+2y-z=4 x+y-z=6 x-3y+2z=1 3x+2y-z=4 2x-y+2z=-17 3x+y-3z=-4 x+y+z=6 2x-y+2z=-17 3x+y-3z=-4 x+y+z=6 2x+5y+4z=6,3x+y-7z=-4,x+y-z=? x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 {x+y+z=0 {4x+2y+z=3 {9x+2y+z=6 解方程组x+y+z=6 x+2y-3z=4 2x-y+z=5