已知x2+xy-2y2=0(y≠0),那么x/y=
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已知x2+xy-2y2=0(y≠0),那么x/y=已知x2+xy-2y2=0(y≠0),那么x/y=已知x2+xy-2y2=0(y≠0),那么x/y=x2+xy-2y2=0(y≠0),(x+2y)(x
已知x2+xy-2y2=0(y≠0),那么x/y=
已知x2+xy-2y2=0(y≠0),那么x/y=
已知x2+xy-2y2=0(y≠0),那么x/y=
x2+xy-2y2=0(y≠0),
(x+2y)(x-y)=0
x+2y=0,x-y=0
x=-2y x=y
x/y=-2 ,x/y=1
x² +xy-2y²= 0
x² -2y²= -xy
x/y-2y/x=-1 (x/y)² +x/y-2=0 (x/y-1)(x/y+2)=0
x/y=1 x/y=-2
由题可变成(x 2y)(x-y)= 0,这里你应该知道了吧
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