已知等差数列的公差d

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已知等差数列的公差d已知等差数列的公差d已知等差数列的公差d由等差数列性质得Sn=(ai+aj)*n/2(i+j=n+1)可得S20=(a10+a11)*10S21=21*a11依题意a10+a11>

已知等差数列的公差d
已知等差数列的公差d

已知等差数列的公差d
由等差数列性质得 Sn=(ai+aj)*n/2 ( i+j=n+1)
可得 S20=(a10+a11)*10
S21=21*a11
依题意 a10+a11>0
a11

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