dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
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dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,化成齐次方程dy/d
dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
化成齐次方程 dy/dx=f(y/x),做变量代换u=y/x,化成可分离变量方程求通解,带入约束条件求出常数得到特解.另,你题目x^-y^这样表述确定没问题么=_=
dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
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