设f(1-x)=x^2-x,则f(x)=?3Q
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设f(1-x)=x^2-x,则f(x)=?3Q设f(1-x)=x^2-x,则f(x)=?3Q设f(1-x)=x^2-x,则f(x)=?3Qf(1-x)=x^2-x==>f[1-(1-x)]=(1-x)
设f(1-x)=x^2-x,则f(x)=?3Q
设f(1-x)=x^2-x,则f(x)=?3Q
设f(1-x)=x^2-x,则f(x)=?3Q
f(1-x) = x^2 - x ==> f[1 - (1-x)] = (1-x)^2 - (1-x) ==> f (x) = (1-x)^2 - (1-x) ==> f (x) = (1-x)(1-x - 1) ==> f (x) = x(x-1)
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